Exercice 4 A = (4x - 5)2-(3x + 1)(4x - 1) B = (x + 2)(x-2)-(2x - 3)(4x - 1) C = (5 - 2x)2-(4x + 7)(4x - 7) D = (1 - 2x)2 - [(x + 2)(x-1)-(3x + 1)(3x - 1)] E = 1

Réponse :

Bonjour:

Explications étape par étape :

A) ( 4X - 5) * 2 - ( 3x + 1 ) * ( 4x - 1)

   = 8 x - 10 - ( 12 x^2 - 3 x + 4 x - 1 )

 = 8 x - 10 - ( 12 x^2 + x - 1 )

 = 8 x - 10 - 12 x^2 - x +1

= 7 x - 9 - 12 x^2

= - 12x^2 + 7x - 9

B) (x + 2)(x-2)-(2x - 3)(4x - 1)

= x^2 - 4 - ( 8x^2 - 2x- 12 x + 3 )

= x^2 - 4 - ( 8x^2 - 14x +3)

= x^2 - 4 - 8x^2 + 14x - 3

= -7x + 14 x - 7