Mathématiques

Question

bonjour pouvez vous m'aider pour ces expressions?

(4x-6)²-3(4x-7)=
(3+6x)(5x-4)+'3+6x)=
(4x+3)²-(4x+3)=
(5x-8)(5x+8)-(5x-8)(3-2x)=
(x+3)(2x+4)-2(5x+6)=
(3x+2)²+(4x+3)²=
(3x+1)(2x-3)+(3-5x)(1-x)=
(4x-12)(2x+3)+3x(x-1)+36=
(2x-3)²+(x+5)²=
(4x+7)²-(2x+1)(3x-2)=

1 Réponse

  • Alors !
    1. (4x-6)²-3(4-7) = 16x² + 48x - 68

    2.(3+6x)(5x-4) = 15x+12+30x²-24x = 30x²-9x+12

    3. (4x+3)²-(4x+3) = 8x²+24x+9-4x+3 = 8x²+20x+12

    4.(5x-8)(5x+8)-(5x-8)(3-2x) = 5x²-64-(5x-8)(3-2x) = 5x²-64-(5x+8)(-3+2x) = 5x²+15x-10x-24+16x=5x²+21x-24.

    5.(x+3)(2x+4)-2(5x+6) = 2x²+4x+6x+12-10x+4 = 2x²+16.

    6.(3x+2)²+(4x+3) = 9x²+12x+4+4x+3 = 9x²+16x+7

    7. (4x-12)(2x+3)+3x(x-1)+36 = 8x²+12x-24x-9+3x²-3x+36 = 11x²-15x+27

    8.(2x-3)²+(x+5)² = 4x²+12x-9+x²+10x+25 = 5x²+22x+16

    9.(4x+7)²-(2x+1)(3x-2) = 16x²+56x+49-6x²-4x+3x-2 = 10x²+55x+47

    Voilà :)

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