calculer et simplifier le plus possible en donnant des étapes intermédiaires A =3 - 2 x 5/3 B = 6(1/3 - 2) + 3 x 7/9 C= 2/3 - 5/3 x 21/15 D = 1 + 3/4 / 7/3 - 2
Mathématiques
COCA31
Question
calculer et simplifier le plus possible en donnant des étapes intermédiaires
A =3 - 2 x 5/3
B = 6(1/3 - 2) + 3 x 7/9
C= 2/3 - 5/3 x 21/15
D = 1 + 3/4 / 7/3 - 2
A =3 - 2 x 5/3
B = 6(1/3 - 2) + 3 x 7/9
C= 2/3 - 5/3 x 21/15
D = 1 + 3/4 / 7/3 - 2
2 Réponse
-
1. Réponse Anonyme
[tex]A = 3 - 2 * \frac{5}{3} [/tex]
[tex]A = 3 - \frac{2*5}{1*3} [/tex]
[tex]A = \frac{3*3}{3} - \frac{10}{3} = [/tex]
[tex]A = \frac{9}{3} - \frac{10}{3} [/tex]
[tex]A = \frac{-1}{3} [/tex] -
2. Réponse nonotata
A =3 - 2 x 5/3
a = 3 -10/3
a = 9/3-10/3
a = -1/3
B = 6(1/3 - 2) + 3 x 7/9
b = 6/3-12+21/9
b = 2-12+7/3
b = -10 +7/3
b = -30/3+7/3
b = -23/3
C= 2/3 - 5/3 x 21/15
c = 2/3 -105/45
c = 2/3 - 21/9
c = 2/3 -7/3
c = -5/3
D = 1 + 3/4 / 7/3 - 2
d = 1+ 3/4x3/7 -2
d = 1 + 9/28 -2
d = 28/28 +9/28 -56/28
d = 37/28 -56/28
d = -19/28